Pre-IB Weekly Quiz 3

This page contains your third weekly quiz! Each week of July and August a new quiz will be published, so that you can make sure you are ready to start the Maths AI course in September with confidence. 

Good luck and let us know how you got on!

1

Find

\({ 5 }^{ -2 }\times { 5 }^{ 5 }\)

When the bases are the same, multiply the exponents only.

\({ =5 }^{ (-2+5) }\)

2

Which of the following graphs is the function y = 3x + 2?

Gradient is 3 and intercept is positive 2.

3

Which of the following is 452756 correctly rounded to 3 significant figures

453000 - the third non zero digit is 2, which becomes 3 because of the 7 that follows

4

If \({ 5 }^{ -1 } =n\), what is the value of \(n\)? (Without a calculator)

n =

\({ 5 }^{ -1 }=\frac { 1 }{ { 5 } } =0.2\)
5

If \(5+9a=10\), what is the value of \(a\)? (to 3sf)

a =

1. Subtract 5 from both sides.

2. divide both sides by 9.

3. Remember to round to three significant figures!

6

If \(-6000=-10f-90\), what is the value of \(f\)? (to 3sf)

f=

1. Add 90 to both sides.

2. divide both sides by -10.

7

If \(4g+5=40-3g\), what is the value of \(g\)? (to 3sf)

g=

1.Add 3g to both sides

2. Subtract 5 from both sides

3. Divide both sides by 7

8

What is the distance between coordinates A and B?

A: (-2,-5)

B:(5, 7)

Use Pythagoras to calculate this:

\(\sqrt{\left(\left(5--2\right)^{2}+\left(7--5\right)^{2}\right)}=13.9.\)

9

What is the longest length of a triangle with shorter sides 12 and 40?

Use Pythagoras to calculate this:

\(\sqrt{\left(12^{2}+40^{2}\right)}\)

10

Rearrange the equation \(y=5x+4\) to make \(x\) the subject

x=

1. Subtract 4 from both sides.

2. Divide both sides by 5